Here are the jamb maths past question download page, go through our listed past questions below and try to answer them in the comment section, then go down the page and download the pdf.

### some maths question you can try

If M represents the median and D the mode of the measurements 5, 9, 3, 5, 8 then (M,D) is 10. If x + 2 and x – 1 are factors ofthe expressions lx + 2kx2 + 24, find the values of l and k
A. (6,5) B. (5,8) C. (5,7) A. l = -6, k = -9 B. l=-2,k=1 C. l=-2,k=-1
D. (5,5) E. (7,5) D. l = 0, k = 1 E. l = 6, k = 0

2. A construction company is owned by two partners X
and Y and it is agreed that their profit will be divided in
the ratio 4:5. at the end of the year. Y received #5,000
more than x. what is the total profit of the company for
the year?
A. #20,000.00 B. P’0#25,000.00 C. #30,000.00
D. #15,000.003 E.#45,000.00

3. Given a regular hexagon, calculate each interior angle
of the hexagon.
A. 600 B. 300 C. 1200
D. 450 E. 1350

4. Solve the following equations
4x – 3 = 3x + y = 2y+ 5x – 12
A. 4x = 5, y=2 B. x=2, y=5 C. x=-2, y= -5
D. x = 5, y=-2 E. x = -5, y= -2

5. If x = 1 is the root of the equation
x
3 – 2×2 – 5x + 6, find the other roots
A. -3and2 B. –2 and2 C. 3and–2
D. 1and3 E. –3and1

6. If x is jointly proportional to the cube of y and the
fourth power of z. In what ratio is x increased or
decreased when y is halved and z is doubled?
A. 4:1 increase B. 2:1 increase C. 1:4 decrease
D. 1: 1 no change E. 3: 4 decrease

7. P Q
S R
In the above figure PQR = 600, QPR = 900
, PRS = 900
,
RPS = 450
, QR= 8cm. Determine PS
A. 23cm B. 46cm C. 2cm
D. 86cm E. 8cm

8. Given that cos z = L, where z is an acute angle find an
expression for Co +Z – cosecz
sec Z + tan z
A. l – L B. L
2
-−L
2 C. -L-−L
1+L L2+L-1 (C1+L) +−L

D. L−. E. L-(L2
-1)
(L1+L2
) +−L
2
1+ 1 – L
2+ 1 – L
2

9. If0.0000152 x 0.00042=Ax 108
,where
11. Make T the subject of the equation
av = 3 2V + T
1- V a 2T
A. 3av/(1-v) B. 2v(1-v)2
– a
2v
2
/2a2v
2
-(1-V)2
C. 2v(1 – v)2 + a3v
2
/ 2a2v
2 + (1 – v)2
D. 2v(1 – v)2
– a
4v
3
/2a3v
3
– (1 – v)3
E. 2v(1-v)3
– a
4v
3
/2a3v
3 + (1-v