Here is neco mathematics answers for 2021, enjoy and share to your friends.

31DCAABCCCDC

41CBDCEDECCE

Maths-THEORY

All are 101% Authentic.

====================================

(1a)

Log¹⁰6+ Log¹⁰45 – Log¹⁰27

Log¹⁰(6*45/27) = Log(270/27)

= Log¹⁰10 = 1

(1b)

8^x = 32

2^3x = 2⁵

:. 3x = 5

x=5/3

(1c) 81⅙/27-⅑ = 3⁴*⅙/3³*-⅑ = 3⅔/3-⅓

:. 3⅔-(-⅓) = 3⅔+⅓ = 3³/³

= 3¹

= 3

===================================

(2a)

(i) Gradient (m) = y¹ – y²/x¹- x²

m = -1-0/2-3 = +1/+1=1

(ii) y – y¹= m(x-x¹)

y-0 = 1(x-3)

y = x-3

y-x+3=0

(2b)

(i) Area of ∆ABC = ½absinϴ

= ½*6*8*sin60

= 3*8*sin60

= 1.73

(ii) Area of parallelogram = absinϴ

= 6*8*sin60

= 48*sin60

= 48*0.8660

= 41.6

(3a)

|PQ| = 12km, |QP| = 12km

Speed from P to Q = 6km/h

Speed from Q to P = (6+x)km/h

Total time taken 3hrs20mins

Speed = distance/time

From P to Q = 6/1*12/t

6t = 12

t = 12/6 = 2hrs

:. Time left = 3hrs 20mins – 2hrs

= 1hr 20mins

From Q to P , Speed = distance/time

6+x = 12/ 1²⁰/⁶⁰

6+x = 12/⁴/³

6+x = 12*3/4

6+x = 9

x = 9-6 = 3

(3b)

x² – (sum)x + product = 0

Sum = ⅔ + ¾= 8+9/12 = 17/12

Products = ⅔*¾ = ½

x² – 17x/12 + ½ = 0

12x² – 17x + 6 = 0

(4a)

Y = x²/ 1+x²

U=x² , V= 1+x²

du/dx = 2x , dv/dx = 2x

dy/dx = (vdu/dx – udv/dx)/v²

= (1+x²)2x – x² * 2x/(1+x²)²

= 2x+2x³-2x³/(1+x²)²

dy/dx = 2x/(1+x²)²

(4b)

⅔(3x +2) = ¾(2x -3

6x +4/3 = 6x -9/4

4(6x +4)= 3(6x-9)

24x +16 = 18x-27

24x-18x = -27-16

6x/6 = -43/6

x = -7⅙

(5)

TABULATE

Mass (kg): 31-40| 41-50| 51-60| 61-70| 71-80| 81-90

F: 3| 10| 15| 12| 6| 4

x: 35.5| 45.5| 55.5| 65.5| 75.5| 85.5

Fx: 106.5| 455| 832.5| 786| 453| 342

Class boundaries: 30.5-40.5| 40.5-50.5| 59.5-60.5| 60.5-70.5| 70.5-80.5| 80.5-90.5

(i) Mean (x-bar) = ∑fx/∑f = 2975/50 = 59.5

:. Mean = 60kg

(ii) Mode = L¹ + ( fm-fa/2fm-fa-fb) c

= 50.5. + (15-10/2*15-10-12)10

= 50.5 +(5/8)10

= 50.5+6.25

:. Mode = 56.75

Mode = 57kg(approx)

(6a)

T² = ar = 6 …… (T¹)

T⁴ = ar³ = 54….. (T²)

Common ratio = T²/T¹

ar³/at = 54/6

r²= 9

r = ± √9 = ±3

r =3

Subtract r=3 in equation T¹

ar= 6

3a=6

a = 6/3 = 2

:. a = 2 , r =3

(i) 1st term is 2

(ii) 5th term T⁵=ar⁴

T⁵ = 2*3⁴

= 2*81

= 162

(6b)

(i)

Let pencil be x

Let pens be y

Let Ruler be z

U= 160

n(x) = 75

n(y) = 87

n(z) = 93

n(xny) =25

n(xnz) = 30

n(ynz) = 47

pd n(xnynz) = x

n(xnynz¹) = 25-x

n(xnzny¹) = 30-x

n(ynznx¹) = 47-x

n(xnynz¹) = 75-(25-x+x+30-x)

= 75 -(55-x)

= 75-55+x

= 20+x

n(ynx¹nz¹) = 87-(25-x+x+47-x)

= 87-(72-x)

= 15+x

n(znx¹ny¹) = 93-(30-x+x+47-x)

= 93-77+x

= 16+x

:. 20+x+25-x+x+30-x+15+x+47-x+16+x=160

= 153+x =160

x = 160-153

x = 7

(ii)

n(xny¹nz¹) = 20+7

= 27

:. 27 pupils has pencils only

(7a)

∆XAB = ∆ABC (corresponding angle)

:. ∆BAD + ADC + ∆ACD = 180( sum of angles at triangle)

x = 50°

(7b)

Using cosine rule

c² = a²+b²- 2abcosC

x² = 6²+8²-2(6)(8)cos120

= 36+64- 96cos120

= 36+64+48

x² = 148

x = √148

x = 12km

Using sine rule

a/sinA = b/sinB

12/sin120 = 6/sinϴ

12sinϴ = 6sin120

Sinϴ = 6sin120/12

Sinϴ = 0.4330

ϴ = sin-¹ 0.4330

ϴ = 25.66

= 26°(approx)

:. The bearing of the boat from its starting point is

360 -(26+80)

360 – 106

= 254°

=================================

(9a)

Distance PQ = ϴ/360 * 2πRcosα

Where ϴ = 11+11 = 22° and α = 12°

PQ = 22/360*2*3.142*6400*cos12°

PQ = 884*787.2*0.9781/360

PQ = 2403.9

Distance QS= ϴ/360 *2πR

Where ϴ = 44-12 = 32°

= 32/360 *2*3.142*6400

= 1286963.2/360 = 3574.9

Total distance= 2403.9+3574.9 = 5978.8

= 5980km( 3 s.f)

(9b)

Average speed = Total distance/Total time = 5978.8/8 = 747.35

= 747km/hr

(9c)

No time difference between Q and S because they are on the same longitude

====================================

More coming like Palliative Rice.

For a clearer picture of the photos down there, You can chat me on Whatsapp with MTN CARD 200.

1. 2. 3. 4. 5. 6. 7. 8. 9. Enjoy

1. Genesis August 9, 2021
• MyScholarshipBaze August 9, 2021
• Madinatu Muhammed August 9, 2021
• MyScholarshipBaze August 9, 2021
2. Ptrrrrr August 9, 2021
• MyScholarshipBaze August 9, 2021
• Destiny August 9, 2021
3. Theresa August 9, 2021
4. Emmanuel August 9, 2021
• MyScholarshipBaze August 9, 2021
5. Chidera August 9, 2021
• MyScholarshipBaze August 9, 2021
• Elvis August 9, 2021
6. Ezhno August 9, 2021
• MyScholarshipBaze August 9, 2021
7. Opeyemi August 9, 2021
• MyScholarshipBaze August 9, 2021
8. YAHYA MUSA August 9, 2021
9. Marvelous August 9, 2021
10. Godswill August 9, 2021
• MyScholarshipBaze August 9, 2021